Supply 12 V; three LEDs at 2 V each; target current 20 mA
Resistor drop 6 V; resistance 300 Ω; dissipation 0.12 WThe LED string drops 3 × 2 = 6 V, leaving 6 V for the resistor. At 0.02 A, 6 ÷ 0.02 = 300 Ω.
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A series resistor can limit current in a small low-voltage DC LED circuit. The calculator subtracts the total LED forward voltage from the supply voltage, divides the remainder by the target current in amperes to obtain resistance, and multiplies drop by current to estimate resistor heat dissipation. It expects a positive voltage across the resistor. This simplified method is for low-power LED strings, not mains-powered luminaires or high-power LED drivers.
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The LED string drops 3 × 2 = 6 V, leaving 6 V for the resistor. At 0.02 A, 6 ÷ 0.02 = 300 Ω.
9 − 4 = 5 V across the resistor; 5 ÷ 0.01 = 500 Ω and 5 × 0.01 = 0.05 W.
No. It is the expected operating heat dissipation under the entered assumptions. Select a resistor rated above it, allowing for ambient temperature and tolerances.
No. Mains circuits need an appropriately certified driver and electrical safety design; high-power LEDs often require regulated constant-current drivers.
Using these sample input values gives the first labelled output above. Ideal resistors; tolerance, thermal limits and frequency response are not included.
No. Replace the examples with your real values. Ideal resistors; tolerance, thermal limits and frequency response are not included.
Using these sample input values gives the first labelled output above. No-load DC divider; attached load changes the output voltage.
No. Replace the examples with your real values. No-load DC divider; attached load changes the output voltage.