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    Construction & Electrical

    LED series resistor and power calculator

    About this tool

    A series resistor can limit current in a small low-voltage DC LED circuit. The calculator subtracts the total LED forward voltage from the supply voltage, divides the remainder by the target current in amperes to obtain resistance, and multiplies drop by current to estimate resistor heat dissipation. It expects a positive voltage across the resistor. This simplified method is for low-power LED strings, not mains-powered luminaires or high-power LED drivers.

    Resistors & LED circuits

    Choose a task. Inputs stay in this page only.

    MAKE IT SIMPLE
    Formula assumptions and scope

    For low-power DC LED strings only; do not replace certified LED drivers.

    Result

    Worked examples

    Supply 12 V; three LEDs at 2 V each; target current 20 mA

    Resistor drop 6 V; resistance 300 Ω; dissipation 0.12 W

    The LED string drops 3 × 2 = 6 V, leaving 6 V for the resistor. At 0.02 A, 6 ÷ 0.02 = 300 Ω.

    Supply 9 V; two LEDs at 2 V each; target current 10 mA

    Resistor drop 5 V; resistance 500 Ω; dissipation 0.05 W

    9 − 4 = 5 V across the resistor; 5 ÷ 0.01 = 500 Ω and 5 × 0.01 = 0.05 W.

    Questions & answers

    Is calculated dissipation the same as the resistor's required rating?

    No. It is the expected operating heat dissipation under the entered assumptions. Select a resistor rated above it, allowing for ambient temperature and tolerances.

    Can I use this for an AC mains lamp or a high-power LED?

    No. Mains circuits need an appropriately certified driver and electrical safety design; high-power LEDs often require regulated constant-current drivers.

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